What are the solutions to the equation solvefor y,y^2=x^2(x+3) ?

The solutions to the equation solvefor y,y^2=x^2(x+3) are y=xsqrt(x+3),y=-xsqrt(x+3)

Find the zeros of solvefor y,y^2=x^2(x+3)

The zeros of solvefor y,y^2=x^2(x+3) are y=xsqrt(x+3),y=-xsqrt(x+3)

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solve for

y, y^{2} = x^{2} (x + 3)

y = x x + 3, y = - x x + 3

Solution steps

y^{2} = x^{2} (x + 3)

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x^{2} (x + 3), y = - x^{2} (x + 3)

Simplify

x^{2} (x + 3) : x x + 3

Simplify

- x^{2} (x + 3) : - x x + 3

y = x x + 3, y = - x x + 3

2 x^{2} + 17 x - 3 = 10 x - 9

5 x^{2} - 80 x + 75 = 0

8 - 2 x^{2} = 0

x^{2} + 8 x + 16 = 9

b, s (t) = b^{2} t

What are the solutions to the equation solvefor y,y^2=x^2(x+3) ?
The solutions to the equation solvefor y,y^2=x^2(x+3) are y=xsqrt(x+3),y=-xsqrt(x+3)
Find the zeros of solvefor y,y^2=x^2(x+3)
The zeros of solvefor y,y^2=x^2(x+3) are y=xsqrt(x+3),y=-xsqrt(x+3)