What are the solutions to the equation (8x+1)^2=64 ?

The solutions to the equation (8x+1)^2=64 are x= 7/8 ,x=-9/8

Find the zeros of (8x+1)^2=64

The zeros of (8x+1)^2=64 are x= 7/8 ,x=-9/8

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(8 x + 1)^{2} = 64

x = \frac{7}{8}, x = - \frac{9}{8}

Decimal Notation

x = 0.875, x = - 1.125

Solution steps

(8 x + 1)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

8 x + 1 = 64 : x = \frac{7}{8}

Solve

8 x + 1 = - 64 : x = - \frac{9}{8}

The solutions to the quadratic equation are:

x = \frac{7}{8}, x = - \frac{9}{8}

n^{2} - 2 n = 15

(x - \frac{1}{4}) (x + \frac{1}{4}) = \frac{3}{16}

5 x - x^{2} = 2 x - 2

w^{2} - 8 w + 7 = - 3

x^{2} - 13 x - 11 = - 7 x + 5

What are the solutions to the equation (8x+1)^2=64 ?
The solutions to the equation (8x+1)^2=64 are x= 7/8 ,x=-9/8
Find the zeros of (8x+1)^2=64
The zeros of (8x+1)^2=64 are x= 7/8 ,x=-9/8