What are the solutions to the equation (x+21)^2=4 ?

The solutions to the equation (x+21)^2=4 are x=-19,x=-23

Find the zeros of (x+21)^2=4

The zeros of (x+21)^2=4 are x=-19,x=-23

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(x + 21)^{2} = 4

x = - 19, x = - 23

Solution steps

(x + 21)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 21 = 4 : x = - 19

Solve

x + 21 = - 4 : x = - 23

The solutions to the quadratic equation are:

x = - 19, x = - 23

5 a^{2} - 17 a + 11 = 0

a^{2} - 5 a + 6 = 0

3 x^{2} - 40 x + 100 = 0

x^{2} + x - 1

x^{2} - 24 x

What are the solutions to the equation (x+21)^2=4 ?
The solutions to the equation (x+21)^2=4 are x=-19,x=-23
Find the zeros of (x+21)^2=4
The zeros of (x+21)^2=4 are x=-19,x=-23