What are the solutions to the equation (3x-2)(4x+1)=0 ?

The solutions to the equation (3x-2)(4x+1)=0 are x= 2/3 ,x=-1/4

Find the zeros of (3x-2)(4x+1)=0

The zeros of (3x-2)(4x+1)=0 are x= 2/3 ,x=-1/4

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(3 x - 2) (4 x + 1) = 0

x = \frac{2}{3}, x = - \frac{1}{4}

Decimal Notation

x = 0.66666 \dots, x = - 0.25

Solution steps

(3 x - 2) (4 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or 4 x + 1 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{1}{4}

n^{2} - n - 19 = 0

x^{2} + 8 x + 9 = 2 x

- 5 x^{2} + 12 x = - 6

x (3 x - 6) - 4 + 9 (x - 1) = 5

x^{2} - 10 x + 25 = 0

What are the solutions to the equation (3x-2)(4x+1)=0 ?
The solutions to the equation (3x-2)(4x+1)=0 are x= 2/3 ,x=-1/4
Find the zeros of (3x-2)(4x+1)=0
The zeros of (3x-2)(4x+1)=0 are x= 2/3 ,x=-1/4