What are the solutions to the equation -18p=p^2+81 ?

The solutions to the equation -18p=p^2+81 are p=-9

Find the zeros of -18p=p^2+81

The zeros of -18p=p^2+81 are p=-9

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- 18 p = p^{2} + 81

p = - 9

Solution steps

- 18 p = p^{2} + 81

Switch sides

p^{2} + 81 = - 18 p

Move

18 p

to the left side

p^{2} + 81 + 18 p = 0

Write in the standard form

a x^{2} + b x + c = 0

p^{2} + 18 p + 81 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 81 = 0

p_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 1}

p = \frac{- 18}{2 \cdot 1}

\frac{- 18}{2 \cdot 1} = - 9

p = - 9

The solution to the quadratic equation is:

p = - 9

r^{2} - r + 1 = 0

4 x^{2} - 36 x = 0

a, 8 a^{2} y^{2} = a^{2} x^{2} - x^{4}

2 y^{2} = 4 - 7 y

x^{2} + 1 = 3 x^{2} - 13

What are the solutions to the equation -18p=p^2+81 ?
The solutions to the equation -18p=p^2+81 are p=-9
Find the zeros of -18p=p^2+81
The zeros of -18p=p^2+81 are p=-9