What are the solutions to the equation 2y^2=4-7y ?

The solutions to the equation 2y^2=4-7y are y= 1/2 ,y=-4

Find the zeros of 2y^2=4-7y

The zeros of 2y^2=4-7y are y= 1/2 ,y=-4

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2 y^{2} = 4 - 7 y

y = \frac{1}{2}, y = - 4

Decimal Notation

y = 0.5, y = - 4

Solution steps

2 y^{2} = 4 - 7 y

Move

7 y

to the left side

2 y^{2} + 7 y = 4

Move

4

to the left side

2 y^{2} + 7 y - 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 4) = 9

y_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- 7 + 9}{2 \cdot 2}, y_{2} = \frac{- 7 - 9}{2 \cdot 2}

y = \frac{- 7 + 9}{2 \cdot 2} : \frac{1}{2}

y = \frac{- 7 - 9}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

y = \frac{1}{2}, y = - 4

x^{2} + 1 = 3 x^{2} - 13

x, x^{2} + y^{2} = 1

4 x^{2} - 40 x - 12 = 0

- 2 x^{2} - 4 x = 0

3 x^{2} - 5 x - 3 = 0

What are the solutions to the equation 2y^2=4-7y ?
The solutions to the equation 2y^2=4-7y are y= 1/2 ,y=-4
Find the zeros of 2y^2=4-7y
The zeros of 2y^2=4-7y are y= 1/2 ,y=-4