What are the solutions to the equation 7x^2+x=2 ?

The solutions to the equation 7x^2+x=2 are x=(-1+sqrt(57))/(14),x=(-1-sqrt(57))/(14)

Find the zeros of 7x^2+x=2

The zeros of 7x^2+x=2 are x=(-1+sqrt(57))/(14),x=(-1-sqrt(57))/(14)

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7 x^{2} + x = 2

x = \frac{- 1 + 57}{14}, x = \frac{- 1 - 57}{14}

Decimal Notation

x = 0.46784 \dots, x = - 0.61070 \dots

Solution steps

7 x^{2} + x = 2

Move

2

to the left side

7 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 7 ( - 2 )}{2 \cdot 7}

1^{2} - 4 \cdot 7 (- 2) = 57

x_{1, 2} = \frac{- 1 \pm 57}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 1 + 57}{2 \cdot 7}, x_{2} = \frac{- 1 - 57}{2 \cdot 7}

x = \frac{- 1 + 57}{2 \cdot 7} : \frac{- 1 + 57}{14}

x = \frac{- 1 - 57}{2 \cdot 7} : \frac{- 1 - 57}{14}

The solutions to the quadratic equation are:

x = \frac{- 1 + 57}{14}, x = \frac{- 1 - 57}{14}

2 x^{2} - 5 x = - 2

2 x^{2} - 5 x - 25 = 0

t^{2} - 75 = 0

4^{2} + 4^{2} = x^{2}

a^{2} + a - 2 = 0

What are the solutions to the equation 7x^2+x=2 ?
The solutions to the equation 7x^2+x=2 are x=(-1+sqrt(57))/(14),x=(-1-sqrt(57))/(14)
Find the zeros of 7x^2+x=2
The zeros of 7x^2+x=2 are x=(-1+sqrt(57))/(14),x=(-1-sqrt(57))/(14)