What are the solutions to the equation 4^2+4^2=x^2 ?

The solutions to the equation 4^2+4^2=x^2 are x=4sqrt(2),x=-4sqrt(2)

Find the zeros of 4^2+4^2=x^2

The zeros of 4^2+4^2=x^2 are x=4sqrt(2),x=-4sqrt(2)

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4^{2} + 4^{2} = x^{2}

x = 42, x = - 42

Decimal Notation

x = 5.65685 \dots, x = - 5.65685 \dots

Solution steps

4^{2} + 4^{2} = x^{2}

Switch sides

x^{2} = 4^{2} + 4^{2}

Simplify

4^{2} + 4^{2} : 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 32, x = - 32

32 = 42

- 32 = - 42

x = 42, x = - 42

a^{2} + a - 2 = 0

5 x^{2} + 4 x - 15 = 0

s^{2} + 2 = 0

8 x^{2} - 11 x = - 3

5 (5 x + 2)^{2} - 15 = 30

What are the solutions to the equation 4^2+4^2=x^2 ?
The solutions to the equation 4^2+4^2=x^2 are x=4sqrt(2),x=-4sqrt(2)
Find the zeros of 4^2+4^2=x^2
The zeros of 4^2+4^2=x^2 are x=4sqrt(2),x=-4sqrt(2)