What are the solutions to the equation 2x^2-5x-25=0 ?

The solutions to the equation 2x^2-5x-25=0 are x=5,x=-5/2

Find the zeros of 2x^2-5x-25=0

The zeros of 2x^2-5x-25=0 are x=5,x=-5/2

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2 x^{2} - 5 x - 25 = 0

x = 5, x = - \frac{5}{2}

Decimal Notation

x = 5, x = - 2.5

Solution steps

2 x^{2} - 5 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 25 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 25) = 15

x_{1, 2} = \frac{- ( - 5 ) \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 15}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 15}{2 \cdot 2}

x = \frac{- ( - 5 ) + 15}{2 \cdot 2} : 5

x = \frac{- ( - 5 ) - 15}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 5, x = - \frac{5}{2}

t^{2} - 75 = 0

4^{2} + 4^{2} = x^{2}

a^{2} + a - 2 = 0

5 x^{2} + 4 x - 15 = 0

s^{2} + 2 = 0

What are the solutions to the equation 2x^2-5x-25=0 ?
The solutions to the equation 2x^2-5x-25=0 are x=5,x=-5/2
Find the zeros of 2x^2-5x-25=0
The zeros of 2x^2-5x-25=0 are x=5,x=-5/2