What are the solutions to the equation -4x^2-80x+112=0 ?

The solutions to the equation -4x^2-80x+112=0 are x=-2(5+4sqrt(2)),x=2(4sqrt(2)-5)

Find the zeros of -4x^2-80x+112=0

The zeros of -4x^2-80x+112=0 are x=-2(5+4sqrt(2)),x=2(4sqrt(2)-5)

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- 4 x^{2} - 80 x + 112 = 0

x = - 2 (5 + 42), x = 2 (42 - 5)

Decimal Notation

x = - 21.31370 \dots, x = 1.31370 \dots

Solution steps

- 4 x^{2} - 80 x + 112 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 ( - 4 ) \cdot 112}{2 ( - 4 )}

(- 80)^{2} - 4 (- 4) \cdot 112 = 642

x_{1, 2} = \frac{- ( - 80 ) \pm 64 2}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 64 2}{2 ( - 4 )}, x_{2} = \frac{- ( - 80 ) - 64 2}{2 ( - 4 )}

x = \frac{- ( - 80 ) + 64 2}{2 ( - 4 )} : - 2 (5 + 42)

x = \frac{- ( - 80 ) - 64 2}{2 ( - 4 )} : 2 (42 - 5)

The solutions to the quadratic equation are:

x = - 2 (5 + 42), x = 2 (42 - 5)

10 - 3 a^{2} = - 2

x^{2} - 2 x - 3 = 0

(t + 1)^{2} + (t - 8)^{2} = 45

x, z = 2 x^{2} + 3 y^{2}

3 (2 w - 3)^{2} - 5 = 70

What are the solutions to the equation -4x^2-80x+112=0 ?
The solutions to the equation -4x^2-80x+112=0 are x=-2(5+4sqrt(2)),x=2(4sqrt(2)-5)
Find the zeros of -4x^2-80x+112=0
The zeros of -4x^2-80x+112=0 are x=-2(5+4sqrt(2)),x=2(4sqrt(2)-5)