What are the solutions to the equation 5q^2+15q+5=-6 ?

The solutions to the equation 5q^2+15q+5=-6 are q=(-15+sqrt(5))/(10),q=(-15-sqrt(5))/(10)

Find the zeros of 5q^2+15q+5=-6

The zeros of 5q^2+15q+5=-6 are q=(-15+sqrt(5))/(10),q=(-15-sqrt(5))/(10)

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5 q^{2} + 15 q + 5 = - 6

q = \frac{- 15 + 5}{10}, q = \frac{- 15 - 5}{10}

Decimal Notation

q = - 1.27639 \dots, q = - 1.72360 \dots

Solution steps

5 q^{2} + 15 q + 5 = - 6

Move

6

to the left side

5 q^{2} + 15 q + 11 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 \cdot 11}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 \cdot 11 = 5

q_{1, 2} = \frac{- 15 \pm 5}{2 \cdot 5}

Separate the solutions

q_{1} = \frac{- 15 + 5}{2 \cdot 5}, q_{2} = \frac{- 15 - 5}{2 \cdot 5}

q = \frac{- 15 + 5}{2 \cdot 5} : \frac{- 15 + 5}{10}

q = \frac{- 15 - 5}{2 \cdot 5} : \frac{- 15 - 5}{10}

The solutions to the quadratic equation are:

q = \frac{- 15 + 5}{10}, q = \frac{- 15 - 5}{10}

x (x - 10) = - 21

4 x^{2} + 4 x - 5 = 0

- 3 x^{2} - 6 = 0

r^{2} - 4 r = 0

- x^{2} - 2 x + 3

What are the solutions to the equation 5q^2+15q+5=-6 ?
The solutions to the equation 5q^2+15q+5=-6 are q=(-15+sqrt(5))/(10),q=(-15-sqrt(5))/(10)
Find the zeros of 5q^2+15q+5=-6
The zeros of 5q^2+15q+5=-6 are q=(-15+sqrt(5))/(10),q=(-15-sqrt(5))/(10)