What are the solutions to the equation 5a^2+15a=0 ?

The solutions to the equation 5a^2+15a=0 are a=0,a=-3

Find the zeros of 5a^2+15a=0

The zeros of 5a^2+15a=0 are a=0,a=-3

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5 a^{2} + 15 a = 0

a = 0, a = - 3

Solution steps

5 a^{2} + 15 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 \cdot 0 = 15

a_{1, 2} = \frac{- 15 \pm 15}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- 15 + 15}{2 \cdot 5}, a_{2} = \frac{- 15 - 15}{2 \cdot 5}

a = \frac{- 15 + 15}{2 \cdot 5} : 0

a = \frac{- 15 - 15}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

a = 0, a = - 3

n^{2} - 81 = 0

- 7 - c^{2} = - 17

4 r^{2} + 18 r + 13 = - 2

- 2 x^{2} - 40 x - 224 = 0

(3 x + 2) (x - 1) = 3 x

What are the solutions to the equation 5a^2+15a=0 ?
The solutions to the equation 5a^2+15a=0 are a=0,a=-3
Find the zeros of 5a^2+15a=0
The zeros of 5a^2+15a=0 are a=0,a=-3