What are the solutions to the equation 4r^2+18r+13=-2 ?

The solutions to the equation 4r^2+18r+13=-2 are r=(-9+sqrt(21))/4 ,r=-(9+sqrt(21))/4

Find the zeros of 4r^2+18r+13=-2

The zeros of 4r^2+18r+13=-2 are r=(-9+sqrt(21))/4 ,r=-(9+sqrt(21))/4

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4 r^{2} + 18 r + 13 = - 2

r = \frac{- 9 + 21}{4}, r = - \frac{9 + 21}{4}

Decimal Notation

r = - 1.10435 \dots, r = - 3.39564 \dots

Solution steps

4 r^{2} + 18 r + 13 = - 2

Move

2

to the left side

4 r^{2} + 18 r + 15 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

1 8^{2} - 4 \cdot 4 \cdot 15 = 221

r_{1, 2} = \frac{- 18 \pm 2 21}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- 18 + 2 21}{2 \cdot 4}, r_{2} = \frac{- 18 - 2 21}{2 \cdot 4}

r = \frac{- 18 + 2 21}{2 \cdot 4} : \frac{- 9 + 21}{4}

r = \frac{- 18 - 2 21}{2 \cdot 4} : - \frac{9 + 21}{4}

The solutions to the quadratic equation are:

r = \frac{- 9 + 21}{4}, r = - \frac{9 + 21}{4}

- 2 x^{2} - 40 x - 224 = 0

(3 x + 2) (x - 1) = 3 x

6 x^{2} + x + 1 = 0

2 k^{2} - 37 = 61

x^{2} - 7 = 9

What are the solutions to the equation 4r^2+18r+13=-2 ?
The solutions to the equation 4r^2+18r+13=-2 are r=(-9+sqrt(21))/4 ,r=-(9+sqrt(21))/4
Find the zeros of 4r^2+18r+13=-2
The zeros of 4r^2+18r+13=-2 are r=(-9+sqrt(21))/4 ,r=-(9+sqrt(21))/4