What are the solutions to the equation 6x^2-12x+6=0 ?

The solutions to the equation 6x^2-12x+6=0 are x=1

Find the zeros of 6x^2-12x+6=0

The zeros of 6x^2-12x+6=0 are x=1

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6 x^{2} - 12 x + 6 = 0

x = 1

Solution steps

6 x^{2} - 12 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 \cdot 6 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 6}

x = \frac{- ( - 12 )}{2 \cdot 6}

\frac{- ( - 12 )}{2 \cdot 6} = 1

x = 1

The solution to the quadratic equation is:

x = 1

9 n^{2} + 10 = 91

5 x^{2} + 15 = 17 x

2 x^{2} - 2 x + 6 = 0

θ^{2} + 54 = 90

x^{2} - 2 x - 62 = x + 8

What are the solutions to the equation 6x^2-12x+6=0 ?
The solutions to the equation 6x^2-12x+6=0 are x=1
Find the zeros of 6x^2-12x+6=0
The zeros of 6x^2-12x+6=0 are x=1