What are the solutions to the equation 8x^2-7x=0 ?

The solutions to the equation 8x^2-7x=0 are x= 7/8 ,x=0

Find the zeros of 8x^2-7x=0

The zeros of 8x^2-7x=0 are x= 7/8 ,x=0

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8 x^{2} - 7 x = 0

x = \frac{7}{8}, x = 0

Decimal Notation

x = 0.875, x = 0

Solution steps

8 x^{2} - 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 7)^{2} - 4 \cdot 8 \cdot 0 = 7

x_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 8}, x_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 8}

x = \frac{- ( - 7 ) + 7}{2 \cdot 8} : \frac{7}{8}

x = \frac{- ( - 7 ) - 7}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = \frac{7}{8}, x = 0

6 x^{2} + 3 x - 5 = 0

9 x^{2} + 10 = 12 x

x^{2} - 18 x - 2 = 0

2 x^{2} - 12 x + 23

v, m g h = \frac{1}{2} m v^{2}

What are the solutions to the equation 8x^2-7x=0 ?
The solutions to the equation 8x^2-7x=0 are x= 7/8 ,x=0
Find the zeros of 8x^2-7x=0
The zeros of 8x^2-7x=0 are x= 7/8 ,x=0