What are the solutions to the equation -4x^2-40x-280=0 ?

The solutions to the equation -4x^2-40x-280=0 are x=-5-3sqrt(5)i,x=-5+3sqrt(5)i

Find the zeros of -4x^2-40x-280=0

The zeros of -4x^2-40x-280=0 are x=-5-3sqrt(5)i,x=-5+3sqrt(5)i

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- 4 x^{2} - 40 x - 280 = 0

x = - 5 - 35 i, x = - 5 + 35 i

Solution steps

- 4 x^{2} - 40 x - 280 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 4 ) ( - 280 )}{2 ( - 4 )}

Simplify

(- 40)^{2} - 4 (- 4) (- 280) : 245 i

x_{1, 2} = \frac{- ( - 40 ) \pm 24 5 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 24 5 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 40 ) - 24 5 i}{2 ( - 4 )}

x = \frac{- ( - 40 ) + 24 5 i}{2 ( - 4 )} : - 5 - 35 i

x = \frac{- ( - 40 ) - 24 5 i}{2 ( - 4 )} : - 5 + 35 i

The solutions to the quadratic equation are:

x = - 5 - 35 i, x = - 5 + 35 i

- 2 x^{2} + 2 x + 12 = 0

4 x^{2} + 256 = 0

- 3 x^{2} + 12 x + 429 = 0

4 (x - 2)^{2} = - 1

2 x^{2} = 22

What are the solutions to the equation -4x^2-40x-280=0 ?
The solutions to the equation -4x^2-40x-280=0 are x=-5-3sqrt(5)i,x=-5+3sqrt(5)i
Find the zeros of -4x^2-40x-280=0
The zeros of -4x^2-40x-280=0 are x=-5-3sqrt(5)i,x=-5+3sqrt(5)i