What are the solutions to the equation x^2+28=0 ?

The solutions to the equation x^2+28=0 are x=2sqrt(7)i,x=-2sqrt(7)i

Find the zeros of x^2+28=0

The zeros of x^2+28=0 are x=2sqrt(7)i,x=-2sqrt(7)i

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x^{2} + 28 = 0

x = 27 i, x = - 27 i

Solution steps

x^{2} + 28 = 0

Move

28

to the right side

x^{2} = - 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 28, x = - - 28

- 28 = 27 i

- - 28 = - 27 i

x = 27 i, x = - 27 i

0 = - x^{2} + 4

x^{2} - 2 = 7

- 5 + 6 x - x^{2}

m^{2} + 2 m + 4 = 0

- x^{2} + 4 x

What are the solutions to the equation x^2+28=0 ?
The solutions to the equation x^2+28=0 are x=2sqrt(7)i,x=-2sqrt(7)i
Find the zeros of x^2+28=0
The zeros of x^2+28=0 are x=2sqrt(7)i,x=-2sqrt(7)i