What are the solutions to the equation 3(3x+4)^2+24=36 ?

The solutions to the equation 3(3x+4)^2+24=36 are x=-2/3 ,x=-2

Find the zeros of 3(3x+4)^2+24=36

The zeros of 3(3x+4)^2+24=36 are x=-2/3 ,x=-2

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3 (3 x + 4)^{2} + 24 = 36

x = - \frac{2}{3}, x = - 2

Decimal Notation

x = - 0.66666 \dots, x = - 2

Solution steps

3 (3 x + 4)^{2} + 24 = 36

Move

24

to the right side

3 (3 x + 4)^{2} = 12

Divide both sides by

3

(3 x + 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 4 = 4 : x = - \frac{2}{3}

Solve

3 x + 4 = - 4 : x = - 2

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 2

x (x - 1) = 72

x^{2} = 2 x^{2} + 4

3 x^{2} + 12 x + 5 = 0

9 x^{2} + 24 x + 16 = 36

r, r^{2} = x^{2} + y^{2}

What are the solutions to the equation 3(3x+4)^2+24=36 ?
The solutions to the equation 3(3x+4)^2+24=36 are x=-2/3 ,x=-2
Find the zeros of 3(3x+4)^2+24=36
The zeros of 3(3x+4)^2+24=36 are x=-2/3 ,x=-2