What are the solutions to the equation 16x^2+9=24x ?

The solutions to the equation 16x^2+9=24x are x= 3/4

Find the zeros of 16x^2+9=24x

The zeros of 16x^2+9=24x are x= 3/4

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16 x^{2} + 9 = 24 x

x = \frac{3}{4}

Decimal Notation

x = 0.75

Solution steps

16 x^{2} + 9 = 24 x

Move

24 x

to the left side

16 x^{2} + 9 - 24 x = 0

Write in the standard form

a x^{2} + b x + c = 0

16 x^{2} - 24 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 \cdot 9}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 24 )}{2 \cdot 16}

\frac{- ( - 24 )}{2 \cdot 16} = \frac{3}{4}

x = \frac{3}{4}

The solution to the quadratic equation is:

x = \frac{3}{4}

- 2 c^{2} + 45 = 27

6 x^{2} + 120 x + 2070 = 0

3 h^{2} - 147 = 0

- 3 x^{2} + 12 x - 120 = 0

x^{2} + 4 x - 285 = 0

What are the solutions to the equation 16x^2+9=24x ?
The solutions to the equation 16x^2+9=24x are x= 3/4
Find the zeros of 16x^2+9=24x
The zeros of 16x^2+9=24x are x= 3/4