What are the solutions to the equation -2c^2+45=27 ?

The solutions to the equation -2c^2+45=27 are c=3,c=-3

Find the zeros of -2c^2+45=27

The zeros of -2c^2+45=27 are c=3,c=-3

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- 2 c^{2} + 45 = 27

c = 3, c = - 3

Solution steps

- 2 c^{2} + 45 = 27

Move

45

to the right side

- 2 c^{2} = - 18

Divide both sides by

- 2

c^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 9, c = - 9

9 = 3

- 9 = - 3

c = 3, c = - 3

6 x^{2} + 120 x + 2070 = 0

3 h^{2} - 147 = 0

- 3 x^{2} + 12 x - 120 = 0

x^{2} + 4 x - 285 = 0

4 (3 x + 4)^{2} - 40 = - 24

What are the solutions to the equation -2c^2+45=27 ?
The solutions to the equation -2c^2+45=27 are c=3,c=-3
Find the zeros of -2c^2+45=27
The zeros of -2c^2+45=27 are c=3,c=-3