What are the solutions to the equation -x^2+6x-4=0 ?

The solutions to the equation -x^2+6x-4=0 are x=3-sqrt(5),x=3+sqrt(5)

Find the zeros of -x^2+6x-4=0

The zeros of -x^2+6x-4=0 are x=3-sqrt(5),x=3+sqrt(5)

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- x^{2} + 6 x - 4 = 0

x = 3 - 5, x = 3 + 5

Decimal Notation

x = 0.76393 \dots, x = 5.23606 \dots

Solution steps

- x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 4) = 25

x_{1, 2} = \frac{- 6 \pm 2 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 5}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 5}{2 ( - 1 )}

x = \frac{- 6 + 2 5}{2 ( - 1 )} : 3 - 5

x = \frac{- 6 - 2 5}{2 ( - 1 )} : 3 + 5

The solutions to the quadratic equation are:

x = 3 - 5, x = 3 + 5

x^{2} + 4 x + 1 = 0

x^{2} + x + 1 = 0

5 n^{2} - 14 n - 12 = 0

x^{2} + 7 x + 10 = 0

3 n^{2} + 16 n + 15 = 1

What are the solutions to the equation -x^2+6x-4=0 ?
The solutions to the equation -x^2+6x-4=0 are x=3-sqrt(5),x=3+sqrt(5)
Find the zeros of -x^2+6x-4=0
The zeros of -x^2+6x-4=0 are x=3-sqrt(5),x=3+sqrt(5)