What are the solutions to the equation -4x^2+40x-120=0 ?

The solutions to the equation -4x^2+40x-120=0 are x=5-sqrt(5)i,x=5+sqrt(5)i

Find the zeros of -4x^2+40x-120=0

The zeros of -4x^2+40x-120=0 are x=5-sqrt(5)i,x=5+sqrt(5)i

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- 4 x^{2} + 40 x - 120 = 0

x = 5 - 5 i, x = 5 + 5 i

Solution steps

- 4 x^{2} + 40 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 4 ) ( - 120 )}{2 ( - 4 )}

Simplify

4 0^{2} - 4 (- 4) (- 120) : 85 i

x_{1, 2} = \frac{- 40 \pm 8 5 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 40 + 8 5 i}{2 ( - 4 )}, x_{2} = \frac{- 40 - 8 5 i}{2 ( - 4 )}

x = \frac{- 40 + 8 5 i}{2 ( - 4 )} : 5 - 5 i

x = \frac{- 40 - 8 5 i}{2 ( - 4 )} : 5 + 5 i

The solutions to the quadratic equation are:

x = 5 - 5 i, x = 5 + 5 i

80 = x^{2} + 1

2 x^{2} + 11 x - 11 = 6 x - 8

- x^{2} + 5 x + 25 = 0

4 x^{2} - 12 x + 1 = 0

3 x^{2} + 33 x + 30 = 0

What are the solutions to the equation -4x^2+40x-120=0 ?
The solutions to the equation -4x^2+40x-120=0 are x=5-sqrt(5)i,x=5+sqrt(5)i
Find the zeros of -4x^2+40x-120=0
The zeros of -4x^2+40x-120=0 are x=5-sqrt(5)i,x=5+sqrt(5)i