What are the solutions to the equation 2x^2+11x-11=6x-8 ?

The solutions to the equation 2x^2+11x-11=6x-8 are x= 1/2 ,x=-3

Find the zeros of 2x^2+11x-11=6x-8

The zeros of 2x^2+11x-11=6x-8 are x= 1/2 ,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 11 x - 11 = 6 x - 8

x = \frac{1}{2}, x = - 3

Decimal Notation

x = 0.5, x = - 3

Solution steps

2 x^{2} + 11 x - 11 = 6 x - 8

Move

8

to the left side

2 x^{2} + 11 x - 3 = 6 x

Move

6 x

to the left side

2 x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 2}, x_{2} = \frac{- 5 - 7}{2 \cdot 2}

x = \frac{- 5 + 7}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 5 - 7}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 3

- x^{2} + 5 x + 25 = 0

4 x^{2} - 12 x + 1 = 0

3 x^{2} + 33 x + 30 = 0

a^{2} - 3 a + 2 = 0

x^{2} + 15 x = 5 x - 24

What are the solutions to the equation 2x^2+11x-11=6x-8 ?
The solutions to the equation 2x^2+11x-11=6x-8 are x= 1/2 ,x=-3
Find the zeros of 2x^2+11x-11=6x-8
The zeros of 2x^2+11x-11=6x-8 are x= 1/2 ,x=-3