What are the solutions to the equation 3^2=1^2+x^2 ?

The solutions to the equation 3^2=1^2+x^2 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of 3^2=1^2+x^2

The zeros of 3^2=1^2+x^2 are x=2sqrt(2),x=-2sqrt(2)

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3^{2} = 1^{2} + x^{2}

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

3^{2} = 1^{2} + x^{2}

Switch sides

1^{2} + x^{2} = 3^{2}

Move

1^{2}

to the right side

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

3 y^{2} - 3 = 0

x^{2} - 2 x - 15 = 0

x^{2} - 4 x - 12 = 0

15 x^{2} + 19 x - 10 = 0

4 (x - 9)^{2} + 25 = 45

What are the solutions to the equation 3^2=1^2+x^2 ?
The solutions to the equation 3^2=1^2+x^2 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of 3^2=1^2+x^2
The zeros of 3^2=1^2+x^2 are x=2sqrt(2),x=-2sqrt(2)