What are the solutions to the equation 12x^2+7x-12=0 ?

The solutions to the equation 12x^2+7x-12=0 are x= 3/4 ,x=-4/3

Find the zeros of 12x^2+7x-12=0

The zeros of 12x^2+7x-12=0 are x= 3/4 ,x=-4/3

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12 x^{2} + 7 x - 12 = 0

x = \frac{3}{4}, x = - \frac{4}{3}

Decimal Notation

x = 0.75, x = - 1.33333 \dots

Solution steps

12 x^{2} + 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 12 ( - 12 )}{2 \cdot 12}

7^{2} - 4 \cdot 12 (- 12) = 25

x_{1, 2} = \frac{- 7 \pm 25}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 7 + 25}{2 \cdot 12}, x_{2} = \frac{- 7 - 25}{2 \cdot 12}

x = \frac{- 7 + 25}{2 \cdot 12} : \frac{3}{4}

x = \frac{- 7 - 25}{2 \cdot 12} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{4}{3}

x^{2} + 5 x = 3 x + 11

(4 x - 1)^{2} = 20 x - 5

a, f = 3 (a + h)^{2} - 7 (a + h) + 2

x, 4 x^{2} + 9 y^{2} - 16 x + 18 y + 61 = 0

m^{2} + 5 m = 2 m^{2}

What are the solutions to the equation 12x^2+7x-12=0 ?
The solutions to the equation 12x^2+7x-12=0 are x= 3/4 ,x=-4/3
Find the zeros of 12x^2+7x-12=0
The zeros of 12x^2+7x-12=0 are x= 3/4 ,x=-4/3