What are the solutions to the equation (4x-1)^2=20x-5 ?

The solutions to the equation (4x-1)^2=20x-5 are x= 3/2 ,x= 1/4

Find the zeros of (4x-1)^2=20x-5

The zeros of (4x-1)^2=20x-5 are x= 3/2 ,x= 1/4

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(4 x - 1)^{2} = 20 x - 5

x = \frac{3}{2}, x = \frac{1}{4}

Decimal Notation

x = 1.5, x = 0.25

Solution steps

(4 x - 1)^{2} = 20 x - 5

Expand

(4 x - 1)^{2} : 16 x^{2} - 8 x + 1

16 x^{2} - 8 x + 1 = 20 x - 5

Move

5

to the left side

16 x^{2} - 8 x + 6 = 20 x

Move

20 x

to the left side

16 x^{2} - 28 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 16 \cdot 6}{2 \cdot 16}

(- 28)^{2} - 4 \cdot 16 \cdot 6 = 20

x_{1, 2} = \frac{- ( - 28 ) \pm 20}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 20}{2 \cdot 16}, x_{2} = \frac{- ( - 28 ) - 20}{2 \cdot 16}

x = \frac{- ( - 28 ) + 20}{2 \cdot 16} : \frac{3}{2}

x = \frac{- ( - 28 ) - 20}{2 \cdot 16} : \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{1}{4}

a, f = 3 (a + h)^{2} - 7 (a + h) + 2

x, 4 x^{2} + 9 y^{2} - 16 x + 18 y + 61 = 0

m^{2} + 5 m = 2 m^{2}

4 x^{2} - 2 x = 3

x^{2} + 2 x + 1 = 3 x + 3

What are the solutions to the equation (4x-1)^2=20x-5 ?
The solutions to the equation (4x-1)^2=20x-5 are x= 3/2 ,x= 1/4
Find the zeros of (4x-1)^2=20x-5
The zeros of (4x-1)^2=20x-5 are x= 3/2 ,x= 1/4