What are the solutions to the equation 2x=x^2+1 ?

The solutions to the equation 2x=x^2+1 are x=1

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2x=x^2+1

2 x = x^{2} + 1

x = 1

Solution steps

2 x = x^{2} + 1

Switch sides

x^{2} + 1 = 2 x

Move

2 x

to the left side

x^{2} + 1 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

x = 1

The solution to the quadratic equation is:

x = 1

- 4 x^{2} - 80 x - 700 = 0

x (x + 1) = 20

2 (x - 3)^{2} + 1 = 73

x^{2} - 35 = 0

9 x^{2} - x = 0

What are the solutions to the equation 2x=x^2+1 ?
The solutions to the equation 2x=x^2+1 are x=1
Find the zeros of 2x=x^2+1
The zeros of 2x=x^2+1 are x=1