What are the solutions to the equation -3w^2-10w+1=-4w^2 ?

The solutions to the equation -3w^2-10w+1=-4w^2 are w=5+2sqrt(6),w=5-2sqrt(6)

Find the zeros of -3w^2-10w+1=-4w^2

The zeros of -3w^2-10w+1=-4w^2 are w=5+2sqrt(6),w=5-2sqrt(6)

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- 3 w^{2} - 10 w + 1 = - 4 w^{2}

w = 5 + 26, w = 5 - 26

Decimal Notation

w = 9.89897 \dots, w = 0.10102 \dots

Solution steps

- 3 w^{2} - 10 w + 1 = - 4 w^{2}

Move

4 w^{2}

to the left side

w^{2} - 10 w + 1 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 1 = 46

w_{1, 2} = \frac{- ( - 10 ) \pm 4 6}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 10 ) + 4 6}{2 \cdot 1}, w_{2} = \frac{- ( - 10 ) - 4 6}{2 \cdot 1}

w = \frac{- ( - 10 ) + 4 6}{2 \cdot 1} : 5 + 26

w = \frac{- ( - 10 ) - 4 6}{2 \cdot 1} : 5 - 26

The solutions to the quadratic equation are:

w = 5 + 26, w = 5 - 26

x^{2} - 19 x + 84 = 0

x^{2} + \frac{2}{3} x + 5

2 x^{2} - 5 = - 3 x

5 x^{2} - 10 x + 3

(7 x + 8) (2 x - 11) = 0

What are the solutions to the equation -3w^2-10w+1=-4w^2 ?
The solutions to the equation -3w^2-10w+1=-4w^2 are w=5+2sqrt(6),w=5-2sqrt(6)
Find the zeros of -3w^2-10w+1=-4w^2
The zeros of -3w^2-10w+1=-4w^2 are w=5+2sqrt(6),w=5-2sqrt(6)