What are the solutions to the equation 25(x^2+1)-12=14 ?

The solutions to the equation 25(x^2+1)-12=14 are x= 1/5 ,x=-1/5

Find the zeros of 25(x^2+1)-12=14

The zeros of 25(x^2+1)-12=14 are x= 1/5 ,x=-1/5

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25 (x^{2} + 1) - 12 = 14

x = \frac{1}{5}, x = - \frac{1}{5}

Decimal Notation

x = 0.2, x = - 0.2

Solution steps

25 (x^{2} + 1) - 12 = 14

Move

12

to the right side

25 (x^{2} + 1) = 26

Divide both sides by

25

x^{2} + 1 = \frac{26}{25}

Move

1

to the right side

x^{2} = \frac{1}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{25}, x = - \frac{1}{25}

\frac{1}{25} = \frac{1}{5}

- \frac{1}{25} = - \frac{1}{5}

x = \frac{1}{5}, x = - \frac{1}{5}

(x - 6) (x - 10) = 60

2 x^{2} - 6 x - 56 = 0

5 (2 x - 10)^{2} - 14 = 21

3 x^{2} + 6 x - 1 = 2 x^{2} + 13 x - 7

5 x^{2} - 6 = 13 x

What are the solutions to the equation 25(x^2+1)-12=14 ?
The solutions to the equation 25(x^2+1)-12=14 are x= 1/5 ,x=-1/5
Find the zeros of 25(x^2+1)-12=14
The zeros of 25(x^2+1)-12=14 are x= 1/5 ,x=-1/5