What are the solutions to the equation 4(2-4x)^2-43=-34 ?

The solutions to the equation 4(2-4x)^2-43=-34 are x= 1/8 ,x= 7/8

Find the zeros of 4(2-4x)^2-43=-34

The zeros of 4(2-4x)^2-43=-34 are x= 1/8 ,x= 7/8

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4 (2 - 4 x)^{2} - 43 = - 34

x = \frac{1}{8}, x = \frac{7}{8}

Decimal Notation

x = 0.125, x = 0.875

Solution steps

4 (2 - 4 x)^{2} - 43 = - 34

Move

43

to the right side

4 (2 - 4 x)^{2} = 9

Divide both sides by

4

(2 - 4 x)^{2} = \frac{9}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 - 4 x = \frac{9}{4} : x = \frac{1}{8}

Solve

2 - 4 x = - \frac{9}{4} : x = \frac{7}{8}

The solutions to the quadratic equation are:

x = \frac{1}{8}, x = \frac{7}{8}

x^{2} - 29 x + 100 = 0

x^{2} + 5 = 2 x

x^{2} + 4 b = 0

v^{2} - 4 v - 3 = 2 v

x^{2} + 225 = 0

What are the solutions to the equation 4(2-4x)^2-43=-34 ?
The solutions to the equation 4(2-4x)^2-43=-34 are x= 1/8 ,x= 7/8
Find the zeros of 4(2-4x)^2-43=-34
The zeros of 4(2-4x)^2-43=-34 are x= 1/8 ,x= 7/8