What are the solutions to the equation -3x^2-12=0 ?

The solutions to the equation -3x^2-12=0 are x=2i,x=-2i

Find the zeros of -3x^2-12=0

The zeros of -3x^2-12=0 are x=2i,x=-2i

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- 3 x^{2} - 12 = 0

x = 2 i, x = - 2 i

Solution steps

- 3 x^{2} - 12 = 0

Move

12

to the right side

- 3 x^{2} = 12

Divide both sides by

- 3

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

2 (12 + 2 x) - \frac{( 3 x - 2 ) ^{2}}{5} = 20

D, D^{2} y - 4 e^{5 x} = 0

4 \cdot 8^{2} = d^{2} + d^{2}

x, \frac{x ^{2} + y ^{3}}{y} - 4 x^{2} y = 4

x^{2} - 5 x + 1 = 0

What are the solutions to the equation -3x^2-12=0 ?
The solutions to the equation -3x^2-12=0 are x=2i,x=-2i
Find the zeros of -3x^2-12=0
The zeros of -3x^2-12=0 are x=2i,x=-2i