What are the solutions to the equation 6x^2-4x+5=0 ?

The solutions to the equation 6x^2-4x+5=0 are x= 1/3+i(sqrt(26))/6 ,x= 1/3-i(sqrt(26))/6

Find the zeros of 6x^2-4x+5=0

The zeros of 6x^2-4x+5=0 are x= 1/3+i(sqrt(26))/6 ,x= 1/3-i(sqrt(26))/6

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6 x^{2} - 4 x + 5 = 0

x = \frac{1}{3} + i \frac{26}{6}, x = \frac{1}{3} - i \frac{26}{6}

Solution steps

6 x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 \cdot 5}{2 \cdot 6}

Simplify

(- 4)^{2} - 4 \cdot 6 \cdot 5 : 226 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 26 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 26 i}{2 \cdot 6}, x_{2} = \frac{- ( - 4 ) - 2 26 i}{2 \cdot 6}

x = \frac{- ( - 4 ) + 2 26 i}{2 \cdot 6} : \frac{1}{3} + i \frac{26}{6}

x = \frac{- ( - 4 ) - 2 26 i}{2 \cdot 6} : \frac{1}{3} - i \frac{26}{6}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{26}{6}, x = \frac{1}{3} - i \frac{26}{6}

t, s = \frac{1}{2} g t^{2}

25 - 70 x + 49 x^{2} = 0

2 x^{2} - 12 x + 11

12 x = 13 - x^{2}

- 2 x^{2} + 7 x + 1 = 17

What are the solutions to the equation 6x^2-4x+5=0 ?
The solutions to the equation 6x^2-4x+5=0 are x= 1/3+i(sqrt(26))/6 ,x= 1/3-i(sqrt(26))/6
Find the zeros of 6x^2-4x+5=0
The zeros of 6x^2-4x+5=0 are x= 1/3+i(sqrt(26))/6 ,x= 1/3-i(sqrt(26))/6