What are the solutions to the equation 4n^2=81 ?

The solutions to the equation 4n^2=81 are n= 9/2 ,n=-9/2

Find the zeros of 4n^2=81

The zeros of 4n^2=81 are n= 9/2 ,n=-9/2

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4 n^{2} = 81

n = \frac{9}{2}, n = - \frac{9}{2}

Decimal Notation

n = 4.5, n = - 4.5

Solution steps

4 n^{2} = 81

Divide both sides by

4

n^{2} = \frac{81}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{81}{4}, n = - \frac{81}{4}

\frac{81}{4} = \frac{9}{2}

- \frac{81}{4} = - \frac{9}{2}

n = \frac{9}{2}, n = - \frac{9}{2}

6 x^{2} - 4 x + 5 = 0

t, s = \frac{1}{2} g t^{2}

25 - 70 x + 49 x^{2} = 0

2 x^{2} - 12 x + 11

12 x = 13 - x^{2}

What are the solutions to the equation 4n^2=81 ?
The solutions to the equation 4n^2=81 are n= 9/2 ,n=-9/2
Find the zeros of 4n^2=81
The zeros of 4n^2=81 are n= 9/2 ,n=-9/2