What are the solutions to the equation 12x^2+12x+3=0 ?

The solutions to the equation 12x^2+12x+3=0 are x=-1/2

Find the zeros of 12x^2+12x+3=0

The zeros of 12x^2+12x+3=0 are x=-1/2

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12 x^{2} + 12 x + 3 = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

12 x^{2} + 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

1 2^{2} - 4 \cdot 12 \cdot 3 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 12}

x = \frac{- 12}{2 \cdot 12}

\frac{- 12}{2 \cdot 12} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

10 - (x - 3)^{2} = 5

4 x^{2} = 20 x - 25

8 x^{2} - 6 x - 9 = 0

4 x^{2} - 23 x + 15 = 0

4 x^{2} + 2 x = 12

What are the solutions to the equation 12x^2+12x+3=0 ?
The solutions to the equation 12x^2+12x+3=0 are x=-1/2
Find the zeros of 12x^2+12x+3=0
The zeros of 12x^2+12x+3=0 are x=-1/2