What are the solutions to the equation (x-5)^2+49=0 ?

The solutions to the equation (x-5)^2+49=0 are x=7i+5,x=-7i+5

Find the zeros of (x-5)^2+49=0

The zeros of (x-5)^2+49=0 are x=7i+5,x=-7i+5

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(x - 5)^{2} + 49 = 0

x = 7 i + 5, x = - 7 i + 5

Solution steps

(x - 5)^{2} + 49 = 0

Move

49

to the right side

(x - 5)^{2} = - 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = - 49 : x = 7 i + 5

Solve

x - 5 = - - 49 : x = - 7 i + 5

The solutions to the quadratic equation are:

x = 7 i + 5, x = - 7 i + 5

e^{3} (x^{2} + 1) = x^{2}

2 x^{2} + 5 - 3 = 0

2 z^{2} = 10

2 x^{2} + 5 = 36

a, a^{2} + b^{2} + c^{2} = 0

What are the solutions to the equation (x-5)^2+49=0 ?
The solutions to the equation (x-5)^2+49=0 are x=7i+5,x=-7i+5
Find the zeros of (x-5)^2+49=0
The zeros of (x-5)^2+49=0 are x=7i+5,x=-7i+5