What are the solutions to the equation 2x^2+5=36 ?

The solutions to the equation 2x^2+5=36 are x=sqrt(31/2),x=-sqrt(31/2)

Find the zeros of 2x^2+5=36

The zeros of 2x^2+5=36 are x=sqrt(31/2),x=-sqrt(31/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 5 = 36

x = \frac{31}{2}, x = - \frac{31}{2}

Decimal Notation

x = 3.93700 \dots, x = - 3.93700 \dots

Solution steps

2 x^{2} + 5 = 36

Move

5

to the right side

2 x^{2} = 31

Divide both sides by

2

x^{2} = \frac{31}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{31}{2}, x = - \frac{31}{2}

a, a^{2} + b^{2} + c^{2} = 0

(x - 7) (x - 7) = 0

y, 2 x^{3} = (3 x y + 1)^{2}

x^{2} - 8 x = 4 x - 38

y^{2} - 16 y + 64 = 0

What are the solutions to the equation 2x^2+5=36 ?
The solutions to the equation 2x^2+5=36 are x=sqrt(31/2),x=-sqrt(31/2)
Find the zeros of 2x^2+5=36
The zeros of 2x^2+5=36 are x=sqrt(31/2),x=-sqrt(31/2)