What are the solutions to the equation 4(6-3x)^2-38=-37 ?

The solutions to the equation 4(6-3x)^2-38=-37 are x= 11/6 ,x= 13/6

Find the zeros of 4(6-3x)^2-38=-37

The zeros of 4(6-3x)^2-38=-37 are x= 11/6 ,x= 13/6

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4 (6 - 3 x)^{2} - 38 = - 37

x = \frac{11}{6}, x = \frac{13}{6}

Decimal Notation

x = 1.83333 \dots, x = 2.16666 \dots

Solution steps

4 (6 - 3 x)^{2} - 38 = - 37

Move

38

to the right side

4 (6 - 3 x)^{2} = 1

Divide both sides by

4

(6 - 3 x)^{2} = \frac{1}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

6 - 3 x = \frac{1}{4} : x = \frac{11}{6}

Solve

6 - 3 x = - \frac{1}{4} : x = \frac{13}{6}

The solutions to the quadratic equation are:

x = \frac{11}{6}, x = \frac{13}{6}

m^{2} + 10 m + 25 = 0

x (2 x + 1) = 0

x, x^{2} + x - 2 = 0

7 v^{2} - 42 = - 35 v

x^{2} - 2 x + 3 = 0

What are the solutions to the equation 4(6-3x)^2-38=-37 ?
The solutions to the equation 4(6-3x)^2-38=-37 are x= 11/6 ,x= 13/6
Find the zeros of 4(6-3x)^2-38=-37
The zeros of 4(6-3x)^2-38=-37 are x= 11/6 ,x= 13/6