What are the solutions to the equation 7x^2+20x+23=0 ?

The solutions to the equation 7x^2+20x+23=0 are x=-10/7+i(sqrt(61))/7 ,x=-10/7-i(sqrt(61))/7

Find the zeros of 7x^2+20x+23=0

The zeros of 7x^2+20x+23=0 are x=-10/7+i(sqrt(61))/7 ,x=-10/7-i(sqrt(61))/7

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7 x^{2} + 20 x + 23 = 0

x = - \frac{10}{7} + i \frac{61}{7}, x = - \frac{10}{7} - i \frac{61}{7}

Solution steps

7 x^{2} + 20 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 7 \cdot 23}{2 \cdot 7}

Simplify

2 0^{2} - 4 \cdot 7 \cdot 23 : 261 i

x_{1, 2} = \frac{- 20 \pm 2 61 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 20 + 2 61 i}{2 \cdot 7}, x_{2} = \frac{- 20 - 2 61 i}{2 \cdot 7}

x = \frac{- 20 + 2 61 i}{2 \cdot 7} : - \frac{10}{7} + i \frac{61}{7}

x = \frac{- 20 - 2 61 i}{2 \cdot 7} : - \frac{10}{7} - i \frac{61}{7}

The solutions to the quadratic equation are:

x = - \frac{10}{7} + i \frac{61}{7}, x = - \frac{10}{7} - i \frac{61}{7}

6 x^{2} + 12 x - 90 = 0

x, (x^{2} + 4) y = 8

16 x^{2} - 8 x + 3 = 0

x^{2} + 12 x = - 22

- 7 - 8 x - x^{2}

What are the solutions to the equation 7x^2+20x+23=0 ?
The solutions to the equation 7x^2+20x+23=0 are x=-10/7+i(sqrt(61))/7 ,x=-10/7-i(sqrt(61))/7
Find the zeros of 7x^2+20x+23=0
The zeros of 7x^2+20x+23=0 are x=-10/7+i(sqrt(61))/7 ,x=-10/7-i(sqrt(61))/7