What are the solutions to the equation x^2+14x+3=0 ?

The solutions to the equation x^2+14x+3=0 are x=-7+sqrt(46),x=-7-sqrt(46)

Find the zeros of x^2+14x+3=0

The zeros of x^2+14x+3=0 are x=-7+sqrt(46),x=-7-sqrt(46)

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x^{2} + 14 x + 3 = 0

x = - 7 + 46, x = - 7 - 46

Decimal Notation

x = - 0.21767 \dots, x = - 13.78232 \dots

Solution steps

x^{2} + 14 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 3 = 246

x_{1, 2} = \frac{- 14 \pm 2 46}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 46}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 46}{2 \cdot 1}

x = \frac{- 14 + 2 46}{2 \cdot 1} : - 7 + 46

x = \frac{- 14 - 2 46}{2 \cdot 1} : - 7 - 46

The solutions to the quadratic equation are:

x = - 7 + 46, x = - 7 - 46

x^{2} - 8 x = 1

- 2 x^{2} + 12 x - 10 = 0

x (3 x - 5) = 0

m^{2} + 10 m + 4 = 0

2 x^{2} - 8 x + 9

What are the solutions to the equation x^2+14x+3=0 ?
The solutions to the equation x^2+14x+3=0 are x=-7+sqrt(46),x=-7-sqrt(46)
Find the zeros of x^2+14x+3=0
The zeros of x^2+14x+3=0 are x=-7+sqrt(46),x=-7-sqrt(46)