What are the solutions to the equation (-2x+3)^2=9 ?

The solutions to the equation (-2x+3)^2=9 are x=0,x=3

Find the zeros of (-2x+3)^2=9

The zeros of (-2x+3)^2=9 are x=0,x=3

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(- 2 x + 3)^{2} = 9

x = 0, x = 3

Solution steps

(- 2 x + 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

- 2 x + 3 = 9 : x = 0

Solve

- 2 x + 3 = - 9 : x = 3

The solutions to the quadratic equation are:

x = 0, x = 3

5 x - 7 x^{2} = 3 x + 4

x^{2} + 3 x = 9

s^{2} + 2 s = 0

x^{2} + 5 = 13

4 (3 x - 8)^{2} = 4

What are the solutions to the equation (-2x+3)^2=9 ?
The solutions to the equation (-2x+3)^2=9 are x=0,x=3
Find the zeros of (-2x+3)^2=9
The zeros of (-2x+3)^2=9 are x=0,x=3