What are the solutions to the equation (3x+2)^2=4 ?

The solutions to the equation (3x+2)^2=4 are x=0,x=-4/3

Find the zeros of (3x+2)^2=4

The zeros of (3x+2)^2=4 are x=0,x=-4/3

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(3 x + 2)^{2} = 4

x = 0, x = - \frac{4}{3}

Decimal Notation

x = 0, x = - 1.33333 \dots

Solution steps

(3 x + 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 4 : x = 0

Solve

3 x + 2 = - 4 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{4}{3}

x^{2} - 9 x + 15 = 0

135 = (2 y + 3) (2 y - 3)

3 x^{2} - x = 5

x^{2} - 6 = 2 - 18 x

- x^{2} - 2 x - 9 = 0

What are the solutions to the equation (3x+2)^2=4 ?
The solutions to the equation (3x+2)^2=4 are x=0,x=-4/3
Find the zeros of (3x+2)^2=4
The zeros of (3x+2)^2=4 are x=0,x=-4/3