What are the solutions to the equation 3x^2-x=5 ?

The solutions to the equation 3x^2-x=5 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6

Find the zeros of 3x^2-x=5

The zeros of 3x^2-x=5 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6

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3 x^{2} - x = 5

x = \frac{1 + 61}{6}, x = \frac{1 - 61}{6}

Decimal Notation

x = 1.46837 \dots, x = - 1.13504 \dots

Solution steps

3 x^{2} - x = 5

Move

5

to the left side

3 x^{2} - x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 5) = 61

x_{1, 2} = \frac{- ( - 1 ) \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 61}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 61}{2 \cdot 3}

x = \frac{- ( - 1 ) + 61}{2 \cdot 3} : \frac{1 + 61}{6}

x = \frac{- ( - 1 ) - 61}{2 \cdot 3} : \frac{1 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 61}{6}, x = \frac{1 - 61}{6}

x^{2} - 6 = 2 - 18 x

- x^{2} - 2 x - 9 = 0

x^{2} - 9 x + 19 = 0

4 x^{2} - 25 x = 0

4 x^{2} + 14 x + 12 = 0

What are the solutions to the equation 3x^2-x=5 ?
The solutions to the equation 3x^2-x=5 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6
Find the zeros of 3x^2-x=5
The zeros of 3x^2-x=5 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6