What are the solutions to the equation x^2-6=2-18x ?

The solutions to the equation x^2-6=2-18x are x=-9+sqrt(89),x=-9-sqrt(89)

Find the zeros of x^2-6=2-18x

The zeros of x^2-6=2-18x are x=-9+sqrt(89),x=-9-sqrt(89)

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x^{2} - 6 = 2 - 18 x

x = - 9 + 89, x = - 9 - 89

Decimal Notation

x = 0.43398 \dots, x = - 18.43398 \dots

Solution steps

x^{2} - 6 = 2 - 18 x

Move

18 x

to the left side

x^{2} - 6 + 18 x = 2

Move

2

to the left side

x^{2} + 18 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 8) = 289

x_{1, 2} = \frac{- 18 \pm 2 89}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 89}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 89}{2 \cdot 1}

x = \frac{- 18 + 2 89}{2 \cdot 1} : - 9 + 89

x = \frac{- 18 - 2 89}{2 \cdot 1} : - 9 - 89

The solutions to the quadratic equation are:

x = - 9 + 89, x = - 9 - 89

- x^{2} - 2 x - 9 = 0

x^{2} - 9 x + 19 = 0

4 x^{2} - 25 x = 0

4 x^{2} + 14 x + 12 = 0

7 x^{2} - 56 x = 0

What are the solutions to the equation x^2-6=2-18x ?
The solutions to the equation x^2-6=2-18x are x=-9+sqrt(89),x=-9-sqrt(89)
Find the zeros of x^2-6=2-18x
The zeros of x^2-6=2-18x are x=-9+sqrt(89),x=-9-sqrt(89)