What are the solutions to the equation x^2-9x+19=0 ?

The solutions to the equation x^2-9x+19=0 are x=(9+sqrt(5))/2 ,x=(9-sqrt(5))/2

Find the zeros of x^2-9x+19=0

The zeros of x^2-9x+19=0 are x=(9+sqrt(5))/2 ,x=(9-sqrt(5))/2

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x^{2} - 9 x + 19 = 0

x = \frac{9 + 5}{2}, x = \frac{9 - 5}{2}

Decimal Notation

x = 5.61803 \dots, x = 3.38196 \dots

Solution steps

x^{2} - 9 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 19 = 5

x_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

x = \frac{- ( - 9 ) + 5}{2 \cdot 1} : \frac{9 + 5}{2}

x = \frac{- ( - 9 ) - 5}{2 \cdot 1} : \frac{9 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 5}{2}, x = \frac{9 - 5}{2}

4 x^{2} - 25 x = 0

4 x^{2} + 14 x + 12 = 0

7 x^{2} - 56 x = 0

x, x^{2} - x y + y^{2} - 3 = 0

x^{2} - 4 x + 7

What are the solutions to the equation x^2-9x+19=0 ?
The solutions to the equation x^2-9x+19=0 are x=(9+sqrt(5))/2 ,x=(9-sqrt(5))/2
Find the zeros of x^2-9x+19=0
The zeros of x^2-9x+19=0 are x=(9+sqrt(5))/2 ,x=(9-sqrt(5))/2