What are the solutions to the equation 2(5x+9)^2+10=28 ?

The solutions to the equation 2(5x+9)^2+10=28 are x=-6/5 ,x=-12/5

Find the zeros of 2(5x+9)^2+10=28

The zeros of 2(5x+9)^2+10=28 are x=-6/5 ,x=-12/5

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2 (5 x + 9)^{2} + 10 = 28

x = - \frac{6}{5}, x = - \frac{12}{5}

Solution steps

2 (5 x + 9)^{2} + 10 = 28

Move

10

to the right side

2 (5 x + 9)^{2} = 18

Divide both sides by

2

(5 x + 9)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 9 = 9 : x = - \frac{6}{5}

Solve

5 x + 9 = - 9 : x = - \frac{12}{5}

The solutions to the quadratic equation are:

x = - \frac{6}{5}, x = - \frac{12}{5}

2 x^{2} + 5 = 5 x^{2} - 37

(x + 3)^{2} - 3 = 49

4 (x^{2} + 6) + 35 x = 0

(x - 7)^{2} + (x + 1)^{2} = 7 (x - 1)^{2} + 43

12 x^{2} - 28 x + 12 = 0

What are the solutions to the equation 2(5x+9)^2+10=28 ?
The solutions to the equation 2(5x+9)^2+10=28 are x=-6/5 ,x=-12/5
Find the zeros of 2(5x+9)^2+10=28
The zeros of 2(5x+9)^2+10=28 are x=-6/5 ,x=-12/5