What are the solutions to the equation (x+3)^2-3=49 ?

The solutions to the equation (x+3)^2-3=49 are x=2sqrt(13)-3,x=-2sqrt(13)-3

Find the zeros of (x+3)^2-3=49

The zeros of (x+3)^2-3=49 are x=2sqrt(13)-3,x=-2sqrt(13)-3

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(x + 3)^{2} - 3 = 49

x = 213 - 3, x = - 213 - 3

Decimal Notation

x = 4.21110 \dots, x = - 10.21110 \dots

Solution steps

(x + 3)^{2} - 3 = 49

Move

3

to the right side

(x + 3)^{2} = 52

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 52 : x = 213 - 3

Solve

x + 3 = - 52 : x = - 213 - 3

The solutions to the quadratic equation are:

x = 213 - 3, x = - 213 - 3

4 (x^{2} + 6) + 35 x = 0

(x - 7)^{2} + (x + 1)^{2} = 7 (x - 1)^{2} + 43

12 x^{2} - 28 x + 12 = 0

x^{2} + 18 x = - 79

1 x^{2} + 4 x + 3 = 0

What are the solutions to the equation (x+3)^2-3=49 ?
The solutions to the equation (x+3)^2-3=49 are x=2sqrt(13)-3,x=-2sqrt(13)-3
Find the zeros of (x+3)^2-3=49
The zeros of (x+3)^2-3=49 are x=2sqrt(13)-3,x=-2sqrt(13)-3