What are the solutions to the equation 4(x^2+6)+35x=0 ?

The solutions to the equation 4(x^2+6)+35x=0 are x=-3/4 ,x=-8

Find the zeros of 4(x^2+6)+35x=0

The zeros of 4(x^2+6)+35x=0 are x=-3/4 ,x=-8

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4 (x^{2} + 6) + 35 x = 0

x = - \frac{3}{4}, x = - 8

Solution steps

4 (x^{2} + 6) + 35 x = 0

Expand

4 (x^{2} + 6) + 35 x : 4 x^{2} + 24 + 35 x

4 x^{2} + 24 + 35 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 35 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 \cdot 4 \cdot 24}{2 \cdot 4}

3 5^{2} - 4 \cdot 4 \cdot 24 = 29

x_{1, 2} = \frac{- 35 \pm 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 35 + 29}{2 \cdot 4}, x_{2} = \frac{- 35 - 29}{2 \cdot 4}

x = \frac{- 35 + 29}{2 \cdot 4} : - \frac{3}{4}

x = \frac{- 35 - 29}{2 \cdot 4} : - 8

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - 8

(x - 7)^{2} + (x + 1)^{2} = 7 (x - 1)^{2} + 43

12 x^{2} - 28 x + 12 = 0

x^{2} + 18 x = - 79

1 x^{2} + 4 x + 3 = 0

(x + 4) (x - 6) = 0

What are the solutions to the equation 4(x^2+6)+35x=0 ?
The solutions to the equation 4(x^2+6)+35x=0 are x=-3/4 ,x=-8
Find the zeros of 4(x^2+6)+35x=0
The zeros of 4(x^2+6)+35x=0 are x=-3/4 ,x=-8