What are the solutions to the equation x^2+18x=-79 ?

The solutions to the equation x^2+18x=-79 are x=-9+sqrt(2),x=-9-sqrt(2)

Find the zeros of x^2+18x=-79

The zeros of x^2+18x=-79 are x=-9+sqrt(2),x=-9-sqrt(2)

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x^{2} + 18 x = - 79

x = - 9 + 2, x = - 9 - 2

Decimal Notation

x = - 7.58578 \dots, x = - 10.41421 \dots

Solution steps

x^{2} + 18 x = - 79

Move

79

to the left side

x^{2} + 18 x + 79 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 79}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 79 = 22

x_{1, 2} = \frac{- 18 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 2}{2 \cdot 1}

x = \frac{- 18 + 2 2}{2 \cdot 1} : - 9 + 2

x = \frac{- 18 - 2 2}{2 \cdot 1} : - 9 - 2

The solutions to the quadratic equation are:

x = - 9 + 2, x = - 9 - 2

1 x^{2} + 4 x + 3 = 0

(x + 4) (x - 6) = 0

3 x^{2} = - 12 x

x, f = (x + y)^{2}

7 x^{2} - 31 x - 20 = 0

What are the solutions to the equation x^2+18x=-79 ?
The solutions to the equation x^2+18x=-79 are x=-9+sqrt(2),x=-9-sqrt(2)
Find the zeros of x^2+18x=-79
The zeros of x^2+18x=-79 are x=-9+sqrt(2),x=-9-sqrt(2)