What are the solutions to the equation (x+4)(x-6)=0 ?

The solutions to the equation (x+4)(x-6)=0 are x=-4,x=6

Find the zeros of (x+4)(x-6)=0

The zeros of (x+4)(x-6)=0 are x=-4,x=6

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(x + 4) (x - 6) = 0

x = - 4, x = 6

Solution steps

(x + 4) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x - 6 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 6 = 0 : x = 6

The solutions to the quadratic equation are:

x = - 4, x = 6

3 x^{2} = - 12 x

x, f = (x + y)^{2}

7 x^{2} - 31 x - 20 = 0

x^{2} - 0.5 x - 5 = 0

x^{2} + \frac{4}{5} x - 8

What are the solutions to the equation (x+4)(x-6)=0 ?
The solutions to the equation (x+4)(x-6)=0 are x=-4,x=6
Find the zeros of (x+4)(x-6)=0
The zeros of (x+4)(x-6)=0 are x=-4,x=6