What are the solutions to the equation solvefor x,f=(x+y)^2 ?

The solutions to the equation solvefor x,f=(x+y)^2 are x=sqrt(f)-y,x=-sqrt(f)-y

Find the zeros of solvefor x,f=(x+y)^2

The zeros of solvefor x,f=(x+y)^2 are x=sqrt(f)-y,x=-sqrt(f)-y

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solve for

x, f = (x + y)^{2}

x = f - y, x = - f - y

Solution steps

f = (x + y)^{2}

Switch sides

(x + y)^{2} = f

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + y = f : x = f - y

Solve

x + y = - f : x = - f - y

The solutions to the quadratic equation are:

x = f - y, x = - f - y

7 x^{2} - 31 x - 20 = 0

x^{2} - 0.5 x - 5 = 0

x^{2} + \frac{4}{5} x - 8

25 x^{2} - 5625 = 0

(m - 2)^{2} = 5 - 2 (2 m + 7) + 6^{2} + 2

What are the solutions to the equation solvefor x,f=(x+y)^2 ?
The solutions to the equation solvefor x,f=(x+y)^2 are x=sqrt(f)-y,x=-sqrt(f)-y
Find the zeros of solvefor x,f=(x+y)^2
The zeros of solvefor x,f=(x+y)^2 are x=sqrt(f)-y,x=-sqrt(f)-y